x^2+10+42=-3x+2

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Solution for x^2+10+42=-3x+2 equation: 



x^2+10+42=-3x+2

We move all terms to the left:

x^2+10+42-(-3x+2)=0

We add all the numbers together, and all the variables

x^2-(-3x+2)+52=0

We get rid of parentheses

x^2+3x-2+52=0

We add all the numbers together, and all the variables

x^2+3x+50=0

a = 1; b = 3; c = +50;
Δ = b2-4ac
Δ = 32-4·1·50
Δ = -191
Delta is less than zero, so there is no solution for the equation

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